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D( t )
t = 0
t = 0
t = 0
t in (-oo:0) U (0:+oo)
t^(5/3)-(25*t^(-1/3)) = 0
t^(5/3)-25*t^(-1/3) = 0
t_1 = t^(1/3)
1*t_1^5-25*t_1^-1 = 0
t_1^5-25*t_1^-1 = 0
t_1^-1*(t_1^6-25) = 0
1*t_1^6 = 25 // : 1
t_1^6 = 25
t_1^6 = 25 // ^ 1/6
abs(t_1) = 25^(1/6)
t_1 = 25^(1/6) or t_1 = -25^(1/6)
1/t_1 = 0
1*t_1^-1 = 0 // : 1
t_1^-1 = 0
t_1 należy do O
t_1 = 25^(1/6)
t^(1/3)-25^(1/6) = 0
1*t^(1/3) = 25^(1/6) // : 1
t^(1/3) = 25^(1/6)
t^(1/3) = 25^(1/6) // ^ 3
t = 5
t_1 = -25^(1/6)
t^(1/3)+25^(1/6) = 0
1*t^(1/3) = -25^(1/6) // : 1
t^(1/3) = -25^(1/6)
( -25^(1/6) < 0 i 1/3 in (0:1) ) => t należy do O
t = 5
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